Fix a change in behavior in 'database show' from 1.8.

In 1.8 and previous versions, one could use any fullword portion of the key
name, including the full key, to obtain the record.  Until this patch, this
did not work for the full key.

Closes issue ASTERISK-18886

Patch: by tilghman
Review: by twilson (http://pastebin.com/7rtu6bpk) on #asterisk-dev


git-svn-id: https://origsvn.digium.com/svn/asterisk/branches/10@345640 65c4cc65-6c06-0410-ace0-fbb531ad65f3

main/db.c

@@ -117,9 +117,9 @@ static void db_sync(void);
 DEFINE_SQL_STATEMENT(put_stmt, "INSERT OR REPLACE INTO astdb (key, value) VALUES (?, ?)")
 DEFINE_SQL_STATEMENT(get_stmt, "SELECT value FROM astdb WHERE key=?")
 DEFINE_SQL_STATEMENT(del_stmt, "DELETE FROM astdb WHERE key=?")
-DEFINE_SQL_STATEMENT(deltree_stmt, "DELETE FROM astdb WHERE key LIKE ? || '/' || '%'")
+DEFINE_SQL_STATEMENT(deltree_stmt, "DELETE FROM astdb WHERE key || '/' LIKE ? || '/' || '%'")
 DEFINE_SQL_STATEMENT(deltree_all_stmt, "DELETE FROM astdb")
-DEFINE_SQL_STATEMENT(gettree_stmt, "SELECT key, value FROM astdb WHERE key LIKE ? || '/' || '%'")
+DEFINE_SQL_STATEMENT(gettree_stmt, "SELECT key, value FROM astdb WHERE key || '/' LIKE ? || '/' || '%'")
 DEFINE_SQL_STATEMENT(gettree_all_stmt, "SELECT key, value FROM astdb")
 DEFINE_SQL_STATEMENT(showkey_stmt, "SELECT key, value FROM astdb WHERE key LIKE '%' || '/' || ?")
 DEFINE_SQL_STATEMENT(create_astdb_stmt, "CREATE TABLE IF NOT EXISTS astdb(key VARCHAR(256), value VARCHAR(256), PRIMARY KEY(key))")