res_fax.c: Fix deadlock in fax_gateway_indicate_t38().

fax_gateway_indicate_t38() calls ast_indicate_data() which cannot be
called with any channel locks already held.  A deadlock can happen if the
function is operating on a local channel.

* Made fax_gateway_indicate_t38() unlock the channel before calling
ast_indicate_data() since fax_gateway_indicate_t38() is always called with
the channel locked.

* Made fax_gateway_indicate_t38() return void since nothing cared about
its return value.

ASTERISK-26203
Reported by: Etienne Lessard

ASTERISK-24822
Reported by: David Brillert

ASTERISK-22732
Reported by: Richard Mudgett

Change-Id: I701ff2d26c5fc23e0d5a48a3fd98759a9fd09407
changes/21/3721/1
Richard Mudgett 9 years ago
parent 141cd42880
commit edca14c8a5

@ -3001,12 +3001,15 @@ static struct ast_frame *fax_gateway_detect_v21(struct fax_gateway *gateway, str
return f;
}
static int fax_gateway_indicate_t38(struct ast_channel *chan, struct ast_channel *active, struct ast_control_t38_parameters *control_params)
/*! \pre chan is locked on entry */
static void fax_gateway_indicate_t38(struct ast_channel *chan, struct ast_channel *active, struct ast_control_t38_parameters *control_params)
{
if (active == chan) {
return ast_indicate_data(chan, AST_CONTROL_T38_PARAMETERS, control_params, sizeof(*control_params));
ast_channel_unlock(chan);
ast_indicate_data(chan, AST_CONTROL_T38_PARAMETERS, control_params, sizeof(*control_params));
ast_channel_lock(chan);
} else {
return ast_queue_control_data(chan, AST_CONTROL_T38_PARAMETERS, control_params, sizeof(*control_params));
ast_queue_control_data(chan, AST_CONTROL_T38_PARAMETERS, control_params, sizeof(*control_params));
}
}

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