Fix a potential deadlock in socket_process. check_provisioning can eventually

call find_callno.  You can't hold a pvt lock while calling find_callno because
it goes through and locks every single one looking for a match.


git-svn-id: https://origsvn.digium.com/svn/asterisk/branches/1.4@79214 65c4cc65-6c06-0410-ace0-fbb531ad65f3
1.4
Russell Bryant 18 years ago
parent 4f8857d608
commit 4f785d7d28

@ -6981,8 +6981,15 @@ retryowner:
/* Ignore if it's already up */
if (ast_test_flag(&iaxs[fr->callno]->state, IAX_STATE_STARTED | IAX_STATE_TBD))
break;
if (ies.provverpres && ies.serviceident && sin.sin_addr.s_addr)
if (ies.provverpres && ies.serviceident && sin.sin_addr.s_addr) {
ast_mutex_unlock(&iaxsl[fr->callno]);
check_provisioning(&sin, fd, ies.serviceident, ies.provver);
ast_mutex_lock(&iaxsl[fr->callno]);
if (!iaxs[fr->callno]) {
ast_mutex_unlock(&iaxsl[fr->callno]);
return 1;
}
}
/* If we're in trunk mode, do it now, and update the trunk number in our frame before continuing */
if (ast_test_flag(iaxs[fr->callno], IAX_TRUNK)) {
int new_callno;
@ -7583,8 +7590,15 @@ retryowner2:
memset(&sin, 0, sizeof(sin));
if (update_registry(iaxs[fr->callno]->peer, &sin, fr->callno, ies.devicetype, fd, ies.refresh))
ast_log(LOG_WARNING, "Registry error\n");
if (ies.provverpres && ies.serviceident && sin.sin_addr.s_addr)
if (ies.provverpres && ies.serviceident && sin.sin_addr.s_addr) {
ast_mutex_unlock(&iaxsl[fr->callno]);
check_provisioning(&sin, fd, ies.serviceident, ies.provver);
ast_mutex_lock(&iaxsl[fr->callno]);
if (!iaxs[fr->callno]) {
ast_mutex_unlock(&iaxsl[fr->callno]);
return 1;
}
}
break;
}
registry_authrequest(iaxs[fr->callno]->peer, fr->callno);

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