It is a normal situation that a task gets put in the scheduler that should run

as soon as possible.  Accept "0" as an acceptable time to run, and also treat
negative as "run now", and don't print a debug message about it.

(inspired by a message asking about the "request to schedule in the past"
 debug message on the -dev list)


git-svn-id: https://origsvn.digium.com/svn/asterisk/branches/1.4@142354 65c4cc65-6c06-0410-ace0-fbb531ad65f3
1.4
Russell Bryant 17 years ago
parent 3cf97e5d90
commit 4b5b6ffa27

@ -201,7 +201,6 @@ static int sched_settime(struct timeval *tv, int when)
*tv = now;
*tv = ast_tvadd(*tv, ast_samp2tv(when, 1000));
if (ast_tvcmp(*tv, now) < 0) {
ast_log(LOG_DEBUG, "Request to schedule in the past?!?!\n");
*tv = now;
}
return 0;
@ -215,11 +214,9 @@ int ast_sched_add_variable(struct sched_context *con, int when, ast_sched_cb cal
{
struct sched *tmp;
int res = -1;
DEBUG(ast_log(LOG_DEBUG, "ast_sched_add()\n"));
if (!when) {
ast_log(LOG_NOTICE, "Scheduled event in 0 ms?\n");
return -1;
}
ast_mutex_lock(&con->lock);
if ((tmp = sched_alloc(con))) {
tmp->id = con->eventcnt++;
@ -241,6 +238,7 @@ int ast_sched_add_variable(struct sched_context *con, int when, ast_sched_cb cal
ast_sched_dump(con);
#endif
ast_mutex_unlock(&con->lock);
return res;
}

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